Answer:
[tex]0.116 m^3/s[/tex]
Explanation:
The volume flow rate of a fluid in a pipe is given by:
[tex]Q=Av[/tex]
where
A is the cross-sectional area of the pipe
v is the speed of the fluid
In this problem, at the initial point we have
v = 0.84 m/s is the speed of the water
r = 0.21 m is the radius of the pipe, so the cross-sectional area is
[tex]A=\pi r^2 = \pi (0.21 m)^2 =0.138 m^2[/tex]
So, the volume flow rate is
[tex]Q=(0.138 m^2)(0.84 m/s)=0.116 m^3/s[/tex]
