Three students used factoring to solve a quadratic equation.



Jordan's Solution Keith's Solution Randall's Solution









The equation was solved correctly by . The solutions of the equation are .

Three students used factoring to solve a quadratic equation Jordans Solution Keiths Solution Randalls Solution The equation was solved correctly by The solution class=
Three students used factoring to solve a quadratic equation Jordans Solution Keiths Solution Randalls Solution The equation was solved correctly by The solution class=
Three students used factoring to solve a quadratic equation Jordans Solution Keiths Solution Randalls Solution The equation was solved correctly by The solution class=

Respuesta :

Answer:

The solution was solved correctly by Keith

The solutions of the equation are x=-5,x=-12

Step-by-step explanation:

we have

[tex]x^{2}+17x+72=12[/tex]

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex]x^{2}+17x=12-72[/tex]

[tex]x^{2}+17x=-60[/tex]

Complete the square. Remember to balance the equation by adding the same constants to each side.

[tex]x^{2}+17x+8.5^{2} =-60+8.5^{2}[/tex]

[tex]x^{2}+17x+72.25 =12.25[/tex]

Rewrite as perfect squares

[tex](x+8.5)^{2}=12.25[/tex]

square root both sides

[tex](x+8.5)=(+/-)3.5[/tex]

[tex]x=-8.5(+/-)3.5[/tex]

[tex]x=-8.5(+)3.5=-5[/tex]

[tex]x=-8.5(-)3.5=-12[/tex]

The solution was solved correctly by Keith

The solutions of the equation are x=-5,x=-12

Answer:

The first box is Keith and the second box is -5,-12

Step-by-step explanation:

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