Answer:
The product is equal to [tex]3\sqrt{15}[/tex]
Step-by-step explanation:
Ok,
First, you have
[tex](3\sqrt{-3})(\sqrt{-5})[/tex]
We must follow the rule for multiplying radicals, in this case:
[tex](3\sqrt[2]{-3})(\sqrt[2]{-5})=(3\sqrt[2]{(-3)(-5)})[/tex]
Note that the types of root, n, have to match, in this case is 2 for each root
Then, we know that two negative numbers multiplied give a positive number, in this case
[tex](3\sqrt[2]{-3} )(\sqrt[2]{-5})=(3\sqrt[2]{(-3)(-5)})=(3\sqrt[2]{(15)})[/tex]
So, the correct answer is [tex](3\sqrt{-3})(\sqrt{-5} )=3\sqrt{15}[/tex]
