Respuesta :
[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{6}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[8-6]^2+[5-(-3)]^2}\implies d=\sqrt{(8-6)^2+(5+3)^2} \\\\\\ d=\sqrt{2^2+8^2}\implies d=\sqrt{68}\implies d\approx 8.24[/tex]
Answer:
B. 8.24 units
Step-by-step explanation:
the distance between two points is given by
√(x₂₋x₁)²+ (y₂-y₁)²
x₂=8, x₁=6
y₂=5, y₁= -3
√(8-6)² + (5- (-3))²
√2²+ (5 + 3)²
√4 + 8²
√4 + 64
√68 = 8.24 units