Answer:
The Supersmack gum has a volume of [tex]V=6.75\pi[/tex] cm^3 or [tex]V=21.2057[/tex] cm^3. So, Supersmack's cylindrical bubble gum has more actual gum than the Megapop gumball
Step-by-step explanation:
Assuming that the radius of the Megapop gumball is 1.5 (the same diameter as Supersmack)
The volume of the cylinder's equation can be written as
[tex]V=\pi (1.5^{2})(3 )[/tex]
This simplifies to
[tex]V=6.75\pi[/tex] cm^3 or [tex]V=21.2057[/tex] cm^3
The volume of the gumball's equation can be written as
[tex]V=\frac{4}{3} \pi (1.5)^{3}[/tex]
This simplifies to
[tex]v=4.5\pi[/tex] cm^3 or [tex]V=14.1371[/tex] cm^3
The Supersmack gum has a volume of [tex]V=6.75\pi[/tex] cm^3 or [tex]V=21.2057[/tex] cm^3. So, Supersmack's cylindrical bubble gum has more actual gum than the Megapop gumball
