How much time elapses before the two kittens collide
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Answer:
6.8 s
Explanation:
Let's say the west end of the field is position 0 m and the east end of the field is position 250 m.
The position of kitten A is:
x = 0 + 25 t
And the position of kitten B is:
x = 250 - 12 t
The kittens collide when they have the same position:
25 t = 250 - 12 t
37 t = 250
t ≈ 6.8 s