A survey find that 61% of people are married. They ask the same group of people and 75% of them have at least one kid. If 48% are married and have one kid what is probability that a person in a survey is married or has a child?

Respuesta :

Answer:

22/25

Step-by-step explanation:

The overlap between the 61% and the 75% is the 48%, which means that 13% of the people are married and have no kids (61-48=13)

The 75% includes the people who have one or more kids, and the people who have one or more kids and are married.

Now all we have to do is 13% + 75% = 88% = 22/25

Using Venn probabilities, it is found that there is a 0.88 = 88% probability that a person in a survey is married or has a child.

What is a Venn probability?

In a Venn probability, two non-independent events are related with each other, as are their probabilities.

The "or probability" is given by:

[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]

In this question, the events are:

  • Event A: Person is married.
  • Event B: Person has a child.

The probabilities are given by:

[tex]P(A) = 0.61, P(B) = 0.75, P(A \cap B) = 0.48[/tex]

Hence:

[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]

[tex]P(A \cup B) = 0.61 + 0.75 - 0.48[/tex]

[tex]P(A \cup B) = 0.88[/tex]

0.88 = 88% probability that a person in a survey is married or has a child.

More can be learned about Venn probabilities at https://brainly.com/question/25698611