Need this to graduate. Math 3- 10 points. Find the function!
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The answer is:
The fourth option,
[tex](f-g)(x)=11x[/tex]
To solve the problem, we must remember the following property of the functions:
Subtraction of functions:
We have that,
[tex](f-g)(x)=f(x)-g(x)[/tex]
We are given the functions:
[tex]f(x)=4x+3[/tex]
and
[tex]g(x)=3-7x[/tex]
So, calculating we have:
[tex](f-g)(x)=f(x)-g(x)[/tex]
[tex](f-g)(x)=(4x+3)-(3-7x)[/tex]
[tex](f-g)(x)=4x+3-3+7x[/tex]
[tex](f-g)(x)=4x+7x+3-3=11x[/tex]
Hence, the answer is the fourth option,
[tex](f-g)(x)=11x[/tex]
Have a nice day!
Answer:
(D) (f-g)(x) = 11x
Step-by-step explanation:
You have:
f(x) = 4x + 3
g(x) = 3 - 7x
You want to do f(x) - g(x)... you simply do the operation on their definition...
f(x) - g(x) = 4x + 3 - (3 - 7x) = 4x + 3 - 3 + 7x = 11 x + 0
So, (f-g)(x) = 11x
You can verify it by placing a value for x in both equations. Let's take x = 3
f(x) = 4x + 3 = 4(3) + 3 = 15
g(x) = 3 - 7x = 3 - 7(3) = -18
f(x) - g(x) = 15 - -18 = 33
(f - g)(x) = 11x = 11 (3) = 33
Yes, (f(x) - g(x)) = (f - g)(x) = 33