Hello!
The answer is:
The third option, the approximate magnitude of the given vector is 9.9 units.
[tex]|A|=9.9units[/tex]
Why?
To calculate the magnitude (length) of a vector, we need to apply the following formula:
[tex]|A|=\sqrt{(A_x)^{2} +(A_y)^{2} }[/tex]
So, we are given the vector:
[tex]A=(7.6,-6.4)[/tex]
Then, substituting and calculating the magnitude of the vector, we have:
[tex]|A|=\sqrt{(7.6)^{2} +(-6.4)^{2}}=\sqrt{57.76+40.96}=\sqrt{98.72}\\\\|A|=\sqrt{98.72}=9.9units[/tex]
Hence, we have that the correct option is the third option, the approximate magnitude of the given vector is 9.9 units.
[tex]|A|=9.9units[/tex]
Have a nice day!
