can someone help me?!!!!!
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Answer:
93 m
Explanation:
We need to find the resultant displacement.
Let's take north as positive y-direction and east as positive direction. We have
- Displacement 1 is 51 m to the north, so the two components are
[tex]x_1 =0\\y_1 = 51 m[/tex]
- Displacement 2 is 45 m [tex]60^{\circ}[/tex] north of east, so the two components are
[tex]x_1 = (45)cos 60^{\circ}=22.5 m\\y_1 = (45) sin 60^{\circ}=39.0 m[/tex]
So to find the resultant displacement we have to sum the components along each direction:
[tex]x=x_1 + x_2 = 0+22.5 m = 22.5 m\\y = y_1 + y_2 = 51 m +39.0 m = 90.0 m[/tex]
And the magnitude of the resultant displacement is
[tex]m=\sqrt{x^2+y^2}=\sqrt{(22.5 m)^2+(90.0 m)^2}=92.8 m \sim 93 m[/tex]