Answer:
[tex]\large\boxed{x=\dfrac{4a^2+3a}{9-2a}}[/tex]
Step-by-step explanation:
[tex]\dfrac{3x-a}{x+2a}=\dfrac{2a}{3}\qquad\text{cross multiply}\\\\(3)(3x-a)=(2a)(x+2a)\qquad\text{use the distributive property}\\\\(3)(3x)+(3)(-a)=(2a)(x)+(2a)(2a)\\\\9x-3a=2ax+4a^2\qquad\text{add}\ 3a\ \text{to both sides}\\\\9x=2ax+4a^2+3a\qquad\text{subtract}\ 2ax\ \text{from both sides}\\\\9x-2ax=4a^2+3a\qquad\text{distributive}\\\\(9-2a)x=4a^2+3a\qquad\text{divide both sides by}\ (9-2a)\neq0\\\\x=\dfrac{4a^2+3a}{9-2a}[/tex]
