The given line segment has a midpoint at (3, 1).

What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?

y = x
y = x – 2
y = 3x
y = 3x − 8

The given line segment has a midpoint at 3 1 What is the equation in slopeintercept form of the perpendicular bisector of the given line segment y x y x 2 y 3x class=

Respuesta :

Answer:

y = 1/3 x.

Step-by-step explanation:

The slope of the given line is

(4 - (-2) / 2 - 4)

=   -3.

So the slope of the line perpendicular to it = -1 / (-3) = 1/3.

This line also passes through the point (3, 1) so its equation is ( by the point-slope form):

y - 1 = 1/3(x - 3)

y - 1 = 1/3x - 1

y = 1/3 x (answer).

Answer: The answer is y= x/3

Step-by-step explanation:

Given  points =(2,4)  and (4,-2) whose mid point is (3,1)

Let the points be named  as A(2,4) and B(4,-2) and mid point as C(3,1)

So slope of AB = [tex]\frac{4-(-2)}{2-4}[/tex]

=[tex]\frac{6}{-2}[/tex]

= -3

We know that   Product of Slope of perpendicular lines = -1

Now slope of the line perpendicular to AB × slope of AB = -1

-3 × m2 =-1

i.e. m2 =[tex]\frac{1}{3}[/tex]

Now equation of perpendicular bisector of AB passing through C(3,1)  is

[tex]y -1 =\frac{1}{3}(x-3)\\[/tex]

[tex]y= 1+\frac{1}{3}x -1[/tex]

[tex]y=\frac{1}{3}x[/tex]

Hence the equation of line is y =x/3