[tex]\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=6\\ b=10\\ h=7 \end{cases}\implies A=\cfrac{7(6+10)}{2} \\\\\\ A=\cfrac{7(16)}{2}\implies A=7(8)\implies A=56[/tex]
Answer:
56
Step-by-step explanation:
[tex]A=\frac{1}{2} (b1+b2)h\\[/tex]
[tex]A=\frac{1}{2} (6+10)7[/tex]
[tex]A=\frac{1}{2} (16)7[/tex]
[tex]A=8*7[/tex]
[tex]A=56[/tex]
