Answer:
-332.86 < µ1 - µ2 < -141.14
Step-by-step explanation:
We will be constructing a 99% confidence interval for a difference of means.
We have 2 samples sizes
Sample 1: (freshmen)
n = 10
x = 1023
s = 68
Sample 2: (sophomores)
n = 14
x = 1257
s = 338
We are to assume normality, but the equality in the population variances. This determines the formula we will use. For this situation, we use t-distribution to find the error, and our degrees of freedom are one less than the size of the smallest sample. In this case, 9 degrees of freedom.
Our t-value is: 3.25
*See attached photo for the construction of the confidence interval