Answer:
x = -1 +/-2i
Step-by-step explanation:
Write the equation in standard form to find the roots, also known as the solutions, zeros, or x-intercepts, of the quadratic.
x² + 2x + 5 = 0
Use the quadratic formula by substituting a= 1, b = 2 and c = 5.
[tex]x = \frac{-2 +/- \sqrt{(-2)^2 - 4(1)(5)} }{2(1)} = \frac{-2 +/-\sqrt{4 -20 } }{2} = \frac{-2 +/-\sqrt{-16 } }{2} = \frac{-2 +/-4i }{2} = -1 +/-2i[/tex]
