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Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16). What is the y-value of P'?

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Answer:

The y-value of P' is -10.

Step-by-step explanation:

It was given that; triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2).

The translation rule is

[tex](x,y)\to (x-2,y-16)[/tex]

To find the image of P, which is P', we have to substitute the coordinates of P(-2,6) to obtain;

[tex]P(-2,6)\to P'(-2-2,6-16)[/tex]

[tex]P(-2,6)\to P'(-4,-10)[/tex]

Hence the y-value of P' is -10.

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