Answer:
410 N
Explanation:
At the highest point, there are two forces pushing the man towards the centre of the cylinder: the normal reaction (N) and his weight (W=mg). The sum of these two forces must be equal to the centripetal force. So we have
[tex]N+mg=m\omega^2 r[/tex] (1)
where
m = 71 kg is the mass of the rider
g = 9.8 m/s^2
r = 8.0 m is the radius of the cylinder
[tex]\omega[/tex] is the angular frequency
The cylinder rotates once every 4.5 s (period), so its angular frequency is
[tex]\omega=\frac{2\pi}{T}=\frac{2\pi}{4.5 s}=1.40 rad/s[/tex]
So by solving eq.(1) for N, we find the force with which the wall pushes the rider:
[tex]N=m\omega^2 r-mg=(71 kg)(1.40 rad/s)^2(8.0m)-(71.0kg)(9.8 m/s^2)=417.5 N \sim 410 N[/tex]
