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What is the factorization of g3 – 125? (g– 5)(g2 + 5g + 10) (g – 25)(g2 + 25g + 625) (g – 5)(g2 + 5g + 25) (g – 25)(g2 + 5g + 125)

Respuesta :

Answer:

(g - 5)(g² + 5g + 25)

Step-by-step explanation:

g³ - 125 is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b² )

here a = g and b = 5, that is

g³ - 125 = g³ - 5³ = (g - 5)(g² + 5g + 25)

Answer:

g – 1 – 5/g+1

Step-by-step explanation: