Answer:
[tex]\large\boxed{\dfrac{3}{4}+\dfrac{-2}{3}=\dfrac{1}{12}}[/tex]
Step-by-step explanation:
[tex]\dfrac{3}{4}+\dfrac{-2}{3}=\dfrac{3}{4}-\dfrac{2}{3}\\\\\text{Find the common denominator:}\ LCD(4, 3)=3\cdot4=12.\\\\\dfrac{3}{4}=\dfrac{3\cdot3}{4\cdot3}=\dfrac{9}{12}\\\\\dfrac{2}{3}=\dfrac{2\cdot4}{3\cdot4}=\dfrac{8}{12}\\\\\dfrac{3}{4}-\dfrac{2}{3}=\dfrac{9}{12}-\dfrac{8}{12}=\dfrac{9-8}{12}=\dfrac{1}{12}[/tex]
