contestada

A charge of 4.5x10^-5 C is placed in an electric field with a strength of 2.0x10^4 N/C. What is the electric force acting on the charge?

Respuesta :

Answer:

0.9 N

Explanation:

The electric force acting on a charge is given by:

[tex]F=qE[/tex]

where

q is the magnitude of the charge

E is the strength of the electric field

In this problem, we have

[tex]q=4.5\cdot 10^{-5}C[/tex] is the charge

[tex]E=2.0\cdot 10^4 N/C[/tex] is the strength of the electric field

Substituting into the equation, we find

[tex]F=(4.5\cdot 10^{-5}C)(2.0\cdot 10^4 N/C)=0.9 N[/tex]

Answer:0.9 N is correct:)))

Explanation: