Respuesta :
Answer:
Step-by-step explanation:
a = m^2 - n^2
m = 3
n = 2
a = 3^ - 2^
a = 5
========
b = 2*m*n
b = 2*3*2
b = 12
==========
c = m^2 + n^2
c = 3^2 + 2^2
c = 9 + 4
c = 13
============
So the three sides are 5,12,13.
Do these three work?
5^2 = 25
12^2 = 144
c^2 = 169
25 + 144 = 169
That's what c^2 =.
The Pythagorean Triple does work in this case.