An outside thermometer reads -4 degrees at 7:00 a.m. By 2:30 p.m. the temperature outside has increased by 11 degrees. At 2:30 p.m. the temperature inside Abram's house is 4 degrees less than 11 times the outside temperature. What was the temperature inside the house then?

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sylvain96 sylvain96 · Answer 1 · 2019-04-14T17:47:46+02:00

Answer:

-169 degrees

Step-by-step explanation:

It doesn't make much sense... but let's answer the question anyway.

First task is to determine what's the temperature outside at 2:30 PM.

We know that it's 11 degrees cooler than it was at 7 AM, so -4 - 11 = -15 degrees.

Abram's house is 4 degrees less than 11 times the outside temperature, so we can express that as:

House = 11 x - 4 - where x is the temperature outside.

If we replace the numbers we get: 11 * (-15) - 4 = -165 - 4 = -169 degrees

Abram's house is an extremely cold freezer!

Ashraf82 Ashraf82 · Answer 2 · 2019-04-14T17:55:29+02:00

Answer:

The temperature inside Abram's house at 2:30 was 73°

Step-by-step explanation:

* Lets describe the situation

- At 7:00 a.m. , the temperature outside Abram's house was -4°

- At 2:30 p.m. , the temperature outside Abram's house has

increased by 11°

* We will add 11 ° to -4° to find the temperature at 2:30

∴ The temperature outside Abram's house = -4 + 11 = 7 at 2:30

- At 2:30 the temperature inside the Abram's house is 4 less

then 11 times the outside temperature

* Lets translate this words to mathematics expression

- Start with 11 times the outside temperature

∵ The outside temperature is 7

∴ 11 × 7 = 77°

- Now find the temperature that less by 4

∵ 77 - 4 = 73

∴ The temperature inside Abram's house at 2:30 was 73°