Describe the key features of a parabola with the equation x2 = 40y.
The value of p is .

The parabola opens .

The coordinates of the focus are .

The equation for the directrix is

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ANSWER

p=10

Opens up

Focus:(0,10)

Directrix: y=-10

EXPLANATION

The given parabola has equation;

[tex] {x}^{2} = 40y[/tex]

We compare this to

[tex] {x}^{2} = 4py[/tex]

This implies that,

[tex]4p = 40[/tex]

Hence,

[tex]p = 10[/tex]

Since p is positive, and the orientation is on the y-axis, the parabola opens up.

The coordinates of the focus are (0,p).

Hence the focus is (0,10).

The equation of the directrix is y=-p.

Therefore the directrix has equation,

[tex]y = - 10[/tex]

The features of the given parabola are; p = 10; It opens up; Focus at (0,10); Directrix at y = -10

What are the features of the parabola?

The general form of equation of parabola is;

x² = 4py

We are given the equation of this parabola as x² = 40y

Thus;

4py = 40y

p = 40y/4y

p = 10

The value of p is positive and it will have its' orientation on the y-axis which means that the parabola opens up.

The coordinates of the focus are (0,p). Since p = 10, then;

The coordinates of the focus are; (0,10).

The equation of the directrix is given as; y =-p.

Thus, the directrix equation is; y = -10

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