The pH at 25°c of a 0.32 m solution of a weak acid that has ka = 9.2 × 10−6. is mathematically given as
pH=2.77
What is the pH at 25°c of a 0.32 m solution?
Question Parameter(s):
the ph at 25°c of a 0.32 m solution
a weak acid that has ka = 9.2 × 10−6.
Generally, the equation for the Chemical reaction is mathematically given as
Ha---->H+ + A-
Therefore
H=\frac{x*x}{0.32-x}
x^2=2.34*10^-6
In conclusion
H+=x
H+=1.71*10^{-3}
pH=2.77
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