What is the are of the following figure if AC = 12, AD = 16.
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Answer:
116
Step-by-step explanation:
∆ABC
A = ½bh = ½ × 12 × 6 = 36
∆ACD
A = ½bh = ½ × 16 × 7 = 56
∆ADE
A = ½bh = ½ × 16 × 3 = 24
ABCDE
A = ∆ABC + ∆ACD +∆ADE = 36 + 56 + 24 = 116
The area of the figure is 116 square units.