Answer:
t = 6.3 days
Step-by-step explanation:
The amount of initial mass is irrelevant when finding the half-life since the remaining mass is always 1/2 of the initial mass.
[tex] \frac { 1 } { 2 } = e ^ { ( - 0 . 1 0 9 2 t ) } [/tex]
Taking [tex] l n [/tex] on both the sides to get:
[tex] ln \frac { 1 } { 2 } = -0.1092t [/tex]
[tex] t = \frac { l n \frac { 1 } { 2 } } { -0.01092} [/tex]
[tex] t = 6.3475 [/tex]
t = 6.3 days
