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A rock is thrown from a cliff into a ravine the function h(t)=-16t^2 +192t + 2560 Describes the height in feet of the rock t seconds After it is thrown. what is the height of the rock in feet eight seconds after it is thrown?

Respuesta :

calculista

Answer:

[tex]3,072\ ft[/tex]

Step-by-step explanation:

we have

[tex]h(t)=-16t^{2} +192t+2,560[/tex]

where

h -----> is the height in feet of the rock

t -----> the time in seconds

For [tex]t=8\ sec[/tex]

substitute the value of t in the function and find the value of h

[tex]h(8)=-16(8)^{2} +192(8)+2,560=3,072\ ft[/tex]

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