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camp tent has a center pole 5 feet high. The sides of the tent make an angle of 55 degrees with the ground. How wide is the tent?

1Choice 1

5.7 feet

2Choice 2

14.2 feet


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Respuesta :

Answer with explanation:

Height of pole = 5 feet

Angle made by tent on both sides of the ground = 55°

[tex]\tan 55^{\circ}=\frac{\text{Perpendicular}}{\text{Base}}\\\\1.428=\frac{5}{B}\\\\B=\frac{5}{1.428}\\\\\text{Base}=3.50[/tex]

⇒Total Width of tent = 3.50 + 3.50 = 7 feet

Choice 1 : 7 feet

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abidemiokin

The width of the tent is 3.49 feet

Angle of elevation and depression

Given the following parameters

Height of pole = 5 feet

Angle of elevation = 55 degrees

The width of the tent will be its adjacent

According to the SOH CAH TOA identity'

tan theta = opp/adj

tan 55 = 5/adj

adj = 5/tan55

adj = 5/1.43

adj = 3.49 feet

Hence the width of the tent is 3.49 feet

Laern more on SOH CAH TOA here: https://brainly.com/question/20734777

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