Respuesta :
Answer:
378 mph
Step-by-step explanation:
When the plane travels with the wind:
Distance = 1680 miles
Time = 4 hours
Rate = 1681 / 4 = 420 mph
When the plane travels against the wind:
Distance = 1680 miles
Time = 5 hours
Rate = 1681 / 5 = 336 mph
Given the above information, we can write the equations:
[tex]x+y=420[/tex]
[tex]x-y=336[/tex]
Adding these equations to get:
[tex]2x=756[/tex]
x = 378 mph
Therefore, 378 mph is the speed of the plane in still air.
Answer:
x = 378 miles/h
Step-by-step explanation:
First we calculate the module of both speeds.
With the wind against
[tex]s = \frac{distance}{time}[/tex]
s = d/t
d = 1680 miles
t = 5 hours
s = 1680/5
s = 336 miles/h
[tex]s = x -y[/tex] Because the wind speed goes in the direction opposite to that of the plane.
[tex]336 = x -y[/tex]
Flying with the wind.
s = 1680/4
s = 420
[tex]s = x + y[/tex] Because the wind speed goes in the same direction as the speed of the plane.
[tex]420 = x + y[/tex]
Now we have a system of 2 equations and 2 unknowns. We wish to find the value of x.
[tex]336 = x -y\\420 = x + y[/tex]
Resolving we have:
[tex]336 = x -y[/tex]
+
[tex]420 = x + y[/tex]
-------------------------
[tex]756 = 2x[/tex]
x = 756/2
x = 378 miles/h
y = 42 miles/h