Respuesta :

[tex]\bf{Hey\ there!}[/tex]

[tex]\bf{Quadratic\ formula\ is:}[/tex][tex]\bf{x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}} \ or \ you\ could\ say\ ax^2+bx+c=0[/tex]

[tex]\bf{\bullet\ First: subtract\ by\ 2x\ on\ your\ sides\ that\ you're\ working\ with}[/tex]

[tex]\bf{Like:x^2+20-2x=2x-2x}[/tex]

[tex]\bf{We\ get:x^2-2x+20=0}[/tex]

[tex]\bf{\bullet \ a=1}\\ \bf{\bullet \ b=-2}\\ \bf{\bullet \ c=20}[/tex]

[tex]\bf{x=\frac{-(-2)\pm\sqrt{(-2)^2-4(1)(20})}{2(1)}[/tex]

[tex]\bf{(-2)^2-4(1)(20)=-76} \\ \\ \bf{2(1)=2}[/tex]

[tex]\bold{-(-2)=-1(-2))=+2}[/tex]

[tex]\bf{x=\frac{2\pm\sqrt{-76}}{2}}[/tex]

[tex]\bf{Thus\ there\ is\ NO\ REAL\ SOLUTIONS}[/tex]

[tex]\text{Good\ luck\ on\ your\ assignment\ and\ enjoy\ your\ day!}[/tex]

[tex]\frak{LoveYourselfFirst:)}[/tex]