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The rectangle shown has a perimeter of 48 cm and the given area. Its length is 6 more than twice its width. Write and solve a system of equations to find the dimensions of the rectangle.

Respuesta :

calculista

Answer:

The length of the rectangle is 18 cm

The width of the rectangle is 6 cm

Step-by-step explanation:

Let

x-----> the length of the rectangle

y----> the width of the rectangle

we know that

The perimeter of the rectangle is

[tex]P=2(x+y)[/tex]

we have

[tex]P=48\ cm[/tex]

so

[tex]48=2(x+y)[/tex] ------> equation A

[tex]x=2y+6[/tex] ------> equation B

Substitute equation B in equation A and solve for y

48=2(2y+6+y)

48=2(3y+6)

48=6y+12

6y=48-12

y=36/6=6 cm

Find the value of x

x=2(6)+6=18 cm

The area of the rectangle is

A=xy

A=18*6

A=108 cm^2

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