Kelly has 236 feet of fence to use to enclose a rectangular space for her dog. She wants the width to be 23 feet. Draw a rectangle that could be the space for Kelley's dog. Label the length and the width

Respuesta :

Answer:

The draw in the attached figure

Step-by-step explanation:

Let

L-----> the length of the rectangle

W----> the width of the rectangle

we know that

The perimeter of a rectangle is equal to

[tex]P=2(L+W)[/tex]

we have

[tex]W=23\ ft[/tex]

so

[tex]P=2L+46[/tex] -----> equation A

[tex]P\leq 236\ ft[/tex]  ----> inequality B

substitute equation A in the inequality B and solve for L

[tex]2L+46\leq 236[/tex]

[tex]2L\leq 236-46[/tex]

[tex]2L\leq 190[/tex]

[tex]L\leq 95\ ft[/tex]

The maximum possible  value of L is 95 ft

therefore

The rectangle could be

Length 95 ft

Width 23 ft

see the attached figure to see the draw

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