Answer:
1.88 N
Explanation:
Given in the question,
force applied by Jason = 4N
angle which it make with the ground = 62°
The angle made with the x-axis is cosine of the angle 62°
Thus, the horizontal component of the force is equal to
F = 4.00(cos62⁰) = 1.88 N
/
/
4N /
/
/ 62°
Ф ------------------------
by using trigonometry identity
cosФ = adjacent / hypotenuse
horizontal force = hypotenuse (cos(Ф))
horizontal force = 4cos(62)
