Answer: [tex]\bold{a)\quad \bigg(-5,\dfrac{3}{2}\bigg)}[/tex]
Step-by-step explanation:
[tex]2x^2+7x-15=0\\\\2(-15)=-30\implies -3\ and\ 10\ \text{have a product of -30 and sum of 7}\\\text{So the quadratic equation is factorable.}\\\text{Use the Grouping Method (replace 7x with 10x and -3x):}\\\\2x^2+10x\quad -3x-15=0\\2x(x+5)\quad -3(x+5)\ =0\\(2x-3)\qquad (x+5)=0\\2x-3=0\qquad and\qquad x+5=0\\\large\boxed{x=\dfrac{3}{2}}\qquad and\qquad \large\boxed{x=-5}[/tex]
