Respuesta :

Answer:

[tex]\frac{31x}{30}[/tex]

Step-by-step explanation:

Before adding we require the fractions to have a common denominator

The lowest common denominator of 2, 5 and 3 is 30, thus

[tex]\frac{15x}{15(2)}[/tex] + [tex]\frac{6x}{6(5)}[/tex] + [tex]\frac{10x}{10(3)}[/tex]

= [tex]\frac{15x}{30}[/tex] + [tex]\frac{6x}{30}[/tex] + [tex]\frac{10x}{30}[/tex]

Add the numerators leaving the denominator

= [tex]\frac{15x+6x+10x}{30}[/tex] = [tex]\frac{31x}{30}[/tex]

tramserran

Answer: [tex]\bold{c)\quad \dfrac{31x}{30}}[/tex]

Step-by-step explanation:

[tex]\dfrac{x}{2}+\dfrac{x}{5}+\dfrac{x}{3}\\\\\text{The LCD of 2, 5, and 3 is }2\cdot 5\cdot 3=30\\\text{Multiply each term so their denominator is 30:}\\\\\\\dfrac{x}{2}\bigg(\dfrac{15}{15}\bigg)+\dfrac{x}{5}\bigg(\dfrac{6}{6}\bigg)+\dfrac{x}{3}\bigg(\dfrac{10}{10}\bigg)\\\\\\=\dfrac{15x}{30}+\dfrac{6x}{30}+\dfrac{10x}{30}\\\\\\=\dfrac{15x+6x+10x}{30}\\\\\\=\large\boxed{\dfrac{31x}{30}}[/tex]

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