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The graph h = −16t^2 + 25t + 15 models the height and time of a ball that was thrown off of a building where h is the height in feet and t is the time in seconds. At about what time did the ball reach the maximum height?

A) 0.80 seconds
B) 1 second
C) 2 seconds
D) 15 seconds

The graph h 16t2 25t 15 models the height and time of a ball that was thrown off of a building where h is the height in feet and t is the time in seconds At abo class=

Respuesta :

Answer:

A

Step-by-step explanation:

If you graph the equation f(x) = -16x^2+25x+15. You would need to pay attention to the x value which is somewhere in between 0.75-0.9.

Another way is to convert the equation into vertex form.

Answer:

Option A.

Step-by-step explanation:

The given function is

[tex]h=-16t^2+25t+15[/tex]

It models the height and time of a ball that was thrown off of a building where h is the height in feet and t is the time in seconds.

If a parabola is defined by function [tex]f(x)=ax^2+bx+c[/tex], then the vertex of the parabola is

[tex]Vertex=(-\dfrac{b}{2a},f(-\dfrac{b}{2a}))[/tex]

In the given function a=-16, b=25 and c=15. It is a downward parabola and vertex of a downward parabola is point of maximum.

We need to find the time at which the height of ball is maximum. It means we need to find the x-coordinate of the vertex.

[tex]-\dfrac{b}{2a}=-\dfrac{25}{2(-16)}=0.78125\approx 0.80[/tex]

It means the ball reach the maximum height at about 0.80 seconds.

Therefore, the correct option is A.

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