Answer:
Explanation:
2H⁺ + 2e⁻ ⇄ 2H
This is a reduction half which occurs at the cathode electrode. As typical with redox reactions in which reduction takes place, we have:
1. Decrease in oxidation number
2. Gain of electrons
There is a gain of two electrons and the hydrogen ion is reduced to a hydrogen atom at the cathode.
In an oxidation half, the opposite happens. We would have a loss of electrons and increase in oxidation number.
