Answer:
[tex]y-5=\frac{4}{11} (x-7)[/tex]
Step-by-step explanation:
We start by first finding the slope by using the slope formula:
[tex]m= \frac{y_{2}-y_{1} }{y_{1}-y_{2} }[/tex]
If we let (7,5) → [tex](x_{1} , y_{1} )[/tex] and (-4,1) → [tex](x_{2} , y_{2} )[/tex] then:
[tex]m = \frac{1-5}{-4-7} = -\frac{4}{-11} =\frac{4}{11}[/tex]
Now that we have the slope, we can find the equation of the line in point-slope formula:
[tex]y-y_{1} = m(x-x_{1} )[/tex]
where m is the slope and [tex]x_{1}[/tex] and [tex]y_{1}[/tex] is a coordinate on the line. I will use the point: (7,5)
The equation in point-slope form is then:
[tex]y-5 = \frac{4}{11} (x-7)[/tex]
