Answer:
pH = 11, The solution is Basic.
Explanation:
We know that;
[OH-] [H+] = 1 × 10^-14
we are given; [OH-] as 1 x 10^ -3 M
Therefore, we can get the [H+] by;
[H+] = 1 × 10^-14/[OH-]
= 1 × 10^-14 M/1 x 10^ -3 M
= 1 × 10^-11 M
But; pH = - log [H+]
Thus,
pH = - log (1 ×10^-11 M)
= 11
pH = 11, which means the solution is basic.