Answer:
[tex]b. \ \boxed{32 \sq. \ units}[/tex]
Step-by-step explanation:
A trapezoid is a quadrilateral where at least one pair of opposite sides are parallel. In a trapezoid, the both parallel sides are known as the bases of the trapezoid. So we have two bases, namely, [tex]b_{1}\,and\,b_{2}[/tex]. Also, the height [tex]H[/tex] of the trapezoid is the length between these two bases that's perpendicular to both sides. So the area of a trapezoid in terms of of [tex]b_{1},b_{2}\:and\:H[/tex] is:
[tex]A=\frac{(b_{1}\text{+}b_{2})h}{2}[/tex]
Since:
[tex]b_{1}=6, \ b_{2}=10, \ and \ H=4[/tex]
The area is:
[tex]A=\frac{(6\text{+}10)4}{2}=\boxed{32 \sq. \ units}[/tex]
