Answer:
0.14 J/g°C.
Explanation:
The amount of heat absorbed by Hg = Q = m.c.ΔT.
where, m is the mass of Hg (m = 50.0 g).
c is the specific heat capacity of Hg = ??? J/g°C.
ΔT is the temperature difference = (final T - initial T = 110.0°C).
∴ The amount of heat absorbed by Hg = Q = m.c.ΔT = 770.0 J.
∴ 770.0 J = (50.0 g)(c)(110.0°C).
∴ c = Q/m.ΔT = (770.0 J)/((50.0 g)(110.0°C) = 0.14 J/g°C.