Answer:
(y+3) (x^2+3)
Step-by-step explanation:
x^2y + 3x^2 + 3y + 9
I will factor by grouping
Taking the first two terms I can factor out x^2
Taking the last two terms I can factor out 3
x^2y + 3x^2 + 3y + 9
x^2(y+3) + 3(y+3)
Now I can factor out (y+3)
(y+3) (x^2+3)
Since(x^2+3) and (y+3) cannot be factored , this is completely factored
Answer:
(y+3) (x^2+3)
x^2y + 3x^2 + 3y + 9
grouping
x^2y + 3x^2 + 3y + 9
x^2(y+3) + 3(y+3)
(y+3) (x^2+3)
