Consider the line that passes through the point P(-3,-3) and is parallel to the line x-4y=7. Write the point-slope equation of the line. Use exact values.

Respuesta :

Answer:

[tex]y +3 = \frac{1}{4}(x+3)[/tex]

Step-by-step explanation:

Parallel lines are lines which do not intersect. As a result the lines have the same slope. Find the slope of the current line and substitute it with the point (-3,-3) into the point slope form of a line. This equation will be the equation of the line parallel that crosses through P.

x - 4y = 7 can be converted into y = 1/4x - 7/4. Its slope is 1/4.

Substitute m = 1.4 and (-3,-3) into the formula below.

[tex](y-y_1)=m(x-x_1)\\y --3 = \frac{1}{4}(x--3) \\y +3 = \frac{1}{4}(x+3)[/tex]