What are the solutions to the inequality (x-3)(x+5) greater than or equal to 0?
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Answer:
C
Step-by-step explanation:
If this was an equation...
(x-3)(x+5) = 0
x = 3, -5
So 3 and -5 are the minimum and the maximums.
So we convert that into an inequality.
-5 <= x <= 3
For this case we must find the solutions of the following inequality:
[tex](x-3)(x+5)\leq0[/tex]
For [tex](x-3)(x+5)=0[/tex]we have the following solutions:
[tex]x=3\\x=-5[/tex]
As a possible solution we have the following intervals:
[tex]x\leq -5\\-5\leq x\leq 3\\x\geq 3[/tex]
We must choose a value included in each of the possible intervals, replace them in the original inequality and verify if it is fulfilled.
[tex](-6-3)(-6+5)\leq 0\\-9*-1\leq0\\ 9\leq0[/tex]
It is not true
[tex](0-3)(0+5)\leq 0\\-3*5\leq 0\\-15\leq0[/tex]
It is true.
ANswer:
Option C