Paul has a spinner with 4 colors green yellow blue and orange he spins the spinner 60 times Paul will spin the spinner an additional 450 times how many times should he expect to land on blue

Assuming the spinner is in perfect working condition and that the colors are equally distributed around the spinner, the chances of it stopping on the blue are the same as the ones stopping on the green or the yellow or the orange.

Paul already completed 60 spins, and will do 450 more... for a total of 510 spins.

Since the chances of landing on blue is roughly 1 out of 4 (25%), the spinner should land on that color 25% of the 510 spins... so

blue color = 0.25 * 510 = 127.5 times...

Of course we have to round that number to get a whole number... so 127.

That's not an absolute number because it cannot be fully predicted, but it should be around that number, not around 10 nor around 400.

claudettoterohil claudettoterohil · Answer 2 · 2021-01-26T08:10:17+01:00

Answer:

105

Step-by-step explanation:

Favorable / Total

Results from table shown below:

Colors/Frequency:

Green 12

Yellow 19

Blue 14

Orange15

Add All the Numbers:

12 + 19 + 14 + 15 = 60

14/60 = X/450

Cross Multiply:

6300/60 = 60X/60

X = 105

Answer: 105 Times Paul should expect the spinner to stop Color BLUE.

Add up all the numbers, 12 + 19 + 14 + 15

Sum = 60

Then Divide the amount of BLUES 14/60 = X/450 = 21/2,

Divide 21/2 to get how many times Paul should spin to stop on BLUE,

So, 21/2 = 10 1/2 or 10.5 , or 105

Hope that helps :)