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A cannonball is launched from the top of a 125-meter high cliff with an initial horizontal speed of 20 m/s. The (x, y) coordinate position of the launch location is designated as the (0, 0) position. Determine the (x, y) coordinate positions of the cannonball at 1-second intervals during its path to the ground. Assume g = ~10 m/s2 , down. (can print out this picture or can copy/paste in paint and add the cannonballs position to it)

Respuesta :

ShyzaSling

Answer:

(20 , -5)

Explanation:

Given in the question.

initial horizontal speed [tex]u_{h}[/tex] = 20m/s

g = -10m/s²

y = u[tex]_{v}[/tex]t + 0.5 • g • t²

(equation for vertical displacement for a horizontally launched projectile)

x = u[tex]_{h}[/tex] • t

(equation for horizontal displacement for a horizontally launched projectile)

Plug values in the equations

y = 0(1) + 0.5(-10)(1)²

y = -5m

Here there is no initial vertical velocity (i.e., a case of a horizontally launched projectile).

x = 20 • (1)

x= 20 m

Since there is no horizontal acceleration, the horizontal distance traveled by the projectile each second is a constant value.

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