So,
The area of a parallelogram is simply base times height, or BH. So, the area of the two parallelograms is 2BH.
The area of a triangle is 1/2bh (to distinguish the triangle's b and h from the parallelogram's). Therefore, the area of the three triangles is 3/2bh.
Adding up all of the areas, we get A = 2BH + 3/2bh.
[tex]total\ blades=\frac{100\ blades}{12in.^2}*\frac{144\ in.^2}{ft.^2}*A_T[/tex]
[tex]\frac{100\ blades}{12in.^2}*\frac{144\ in.^2}{ft.^2}=\frac{1.2*10^2\ blades}{ft.^2}[/tex]
[tex]\frac{2\ ft.}{pace}[/tex]
[tex]A_T=A_Q+A_R[/tex]
[tex]A_Q=\frac{3}{4}(8\ paces*\frac{2\ ft.}{pace})^2=48\ ft.^2[/tex]
[tex]A_R=14\ paces*\frac{2\ ft.}{pace}*7\ paces*\frac{2\ ft.}{pace}=392\ ft.^2[/tex]
[tex]A_T=392+48\approx4.5*10^2\ ft.^2[/tex]
[tex]\frac{1.2*10^2\ blades}{ft.^2}*4.5*10^2\ ft.^2=5.4*10^4\ blades[/tex]
