Respuesta :

carlosego

Answer: 34

Step-by-step explanation:

The scale of factor is 2. Then, you must multiply the coordinates of the endpoints AB by 2 to obtain the coordinates od the enpoints A'B':

[tex](0*2,-7(2))=(0-14)[/tex]

[tex](8*2,8*2)=(16,16)[/tex]

Substitute values into the formula, then you obtain that the length A'B' is:

[tex]d=\sqrt{(16-0)^2+(16-(-14))^2}\\d=34[/tex]

zainebamir540

Answer:

d   = √1156 units

Step-by-step explanation:

We have given end-points of AB.

(0,-7) and (8,8)

We have to find length of A⁰B⁰.

Scale factor is 2.

Hence, end-points of A⁰B⁰ are

2(0,-7) and 2(8,8)

(0,-14) and (16,16)

Hence, we can find length of A⁰B⁰ by using distance formula.

d   = √(x₂-x₁)²+(y₂-y₁)²

Putting values ,we have

d  = √(16-0)²+(16-(-14))²

d   = √(16)²+(16+14)²

d   = √256+900

d   = √1156 units which is the answer.

Otras preguntas