The Keq for the reaction of the ammonia formation has been the 1.125 mol/L. Thus, option D is correct.
Keq has been the equilibrium constant for the chemical reaction. The Keq can be calculated from the balanced chemical equation and has been the ratio of the concentration of the product to the reactants with respect to the stoichiometric constants.
The balanced chemical equation for the reaction has been:
[tex]\rm N_2\;+\;3\;H_2\;\rightarrow\;2\;NH_3[/tex]
The equilibrium constant can be given as:
Equilibrium constant = [tex]\rm \dfrac{[NH_3]^2}{[N_2]\;[H_2]^3}[/tex]
The given concentrations of the compounds have been:
Ammonia = 3 M, Nitrogen = 1 M, and Hydrogen = 2 M.
Substituting the values:
Equilibrium constant = [tex]\rm \dfrac{[3]^2}{[1]\;[2]^3}[/tex]
Equilibrium constant = [tex]\rm \dfrac{9}{1\;\times\;8}[/tex]
Equilibrium constant = 1.125 mol/L.
The Keq for the reaction of the ammonia formation has been the 1.125 mol/L. Thus, option D is correct.
For more information about the Keq (Equilibrium constant), refer to the link:
https://brainly.com/question/19671384
Answer:
The answer is Keq = 4.5
Explanation:
Just got it WRONG cuz of the other answer.......
