A gas sample has a pressure of 2.35 atm when the temperature is -15

c. what is the final pressure, in atmospheres, when the temperature is 46 c, with no change in the volume or the amount of gas

Respuesta :

Gay-Lussacs law states that for a fixed amount of gas,  pressure  is directly proportional to absolute temperature, that is temperature in kelvin scale

[tex]\frac{P1}{T1} = \frac{P2}{T2}[/tex]

where P1 is pressure and T1 is temperature at the first instance

and P2 is pressure and T2 is temperature at the second instance

temperature has been given in the celsius scale therefore we have to convert to kelvin scale

T1 --> -15 °C + 273 = 258 K

T2 --> 46 °C + 273 = 319 K

substituting the values in the above equation

[tex]\frac{2.35 atm}{258K} = \frac{P2}{319K}[/tex]

P2 = 2.91 atm

therefore final pressure is 2.91 atm